Let Us Solve. Also, identify remainder (if any) in the division problems. a) 237 × 28 b) 140 × 16 c) 389 × 57 d) 807 ÷ 24 e) 692 ÷ 33 f) 996 ÷ 45

(a) 237 × 28 = 6636 (b) 140 × 16 = 2240 (c) 389 × 57 = 22173 (d) 807 ÷ 24 = 33 remainder 15 (e) 692 ÷ 33 = 20 remainder 32 (f) 996 ÷ 45 = 22 remainder 6 — (a) 237 × 28 = 237 × 20 + 237 × 8 = 4740 + 1896 = 6636 (b) 140 × 16 = 140 × 10 + 140 × 6 = 1400 + 840 = 2240 (c) 389 × 57 = 389 × 50 + 389 × 7 = 19450 + 2723 = 22173 (d) 24 × 33 = 792, 807 - 792 = 15, so remainder is 15 (e) 33 × 20 = 660, 692 - 660 = 32, so remainder is 32 (f) 45 × 22 = 990, 996 - 990 = 6, so remainder is 6

Let Us Solve. Also, identify remainder (if any) in the division…

Question 32 of 42intermediate🔧 ApplyNumerical6 marks

Let Us Solve. Also, identify remainder (if any) in the division problems. a) $237 \times 28$ b) $140 \times 16$ c) $389 \times 57$ d) $807 \div 24$ e) $692 \div 33$ f) $996 \div 45$

(a)

Answer

$237 \times 28 = 6636$

(b)

Answer

$140 \times 16 = 2240$

(c)

Answer

$389 \times 57 = 22173$

(d)

Answer

$807 \div 24 = 33$ remainder $15$

(e)

Answer

$692 \div 33 = 20$ remainder $32$

(f)

Answer

$996 \div 45 = 22$ remainder $6$

Explanation

(a) $237 \times 28 = 237 \times 20 + 237 \times 8 = 4740 + 1896 = 6636$ (b) $140 \times 16 = 140 \times 10 + 140 \times 6 = 1400 + 840 = 2240$ (c) $389 \times 57 = 389 \times 50 + 389 \times 7 = 19450 + 2723 = 22173$ (d) $24 \times 33 = 792$ , $807 - 792 = 15$ , so remainder is 15 (e) $33 \times 20 = 660$ , $692 - 660 = 32$ , so remainder is 32 (f) $45 \times 22 = 990$ , $996 - 990 = 6$ , so remainder is 6

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