Five friends plan to visit an amusement park nearby. Each of them uses different notes and coins to buy the ticket. The cost of the ticket is ₹ 750.
- Bujji has brought all notes of ₹ 200.
- And Munna has brought all notes of ₹ 50.
- Whereas Balu has brought all notes of ₹ 20.
- And guess what, Chinnu has all coins of ₹ 5.
- And Sansu has all coins of ₹ 2. a) Find out how many notes/coins each child has to bring to buy the ticket. b) Which of these children will not receive any change from the cashier? c) How long would the cashier take to count Chinnu's coins?
Bujji: 4 notes of ₹200 (₹800, gets ₹50 change). Munna: 15 notes of ₹50. Balu: 38 notes of ₹20 (₹760, gets ₹10 change). Chinnu: 150 coins of ₹5. Sansu: 375 coins of ₹2.
Munna (₹50 notes), Chinnu (₹5 coins), and Sansu (₹2 coins) will not receive any change because 750 is divisible by 50, 5, and 2.
The cashier would take a considerable amount of time to count 150 coins of ₹5, likely several minutes.
Explanation
(a) Bujji: , so 4 notes needed. Munna: notes. Balu: , so 38 notes needed. Chinnu: coins. Sansu: coins. (b) 750 is divisible by 50, 5, and 2, so these children can pay the exact amount. (c) Counting 150 individual coins is time-consuming compared to counting fewer notes of larger denominations.