Question 9 of 44intermediate🔧 ApplyShort Answer3 marks

If the cat and the rat land on the same number, the cat will catch the rat. The cat is now on 6 and the rat on 12. When the cat jumps 3 steps forward, the rat jumps 2 steps forward. Will the cat catch the rat? If yes, at which number?

Correct Answer

Step 1: Cat starts at 6, jumps 3 steps: positions after n jumps = 6 + 3n

Step 2: Rat starts at 12, jumps 2 steps: positions after n jumps = 12 + 2n

Step 3: Set positions equal to find when they land on the same number at the same time: 6 + 3n = 12 + 2n

Step 4: Solve for n: 3n - 2n = 12 - 6 → n = 6

Step 5: Calculate the position at n = 6: Cat is at 6 + 3(6) = 24, Rat is at 12 + 2(6) = 24

Step 6: Both meet at 24 after 6 jumps, so cat catches rat at 24.

Answer: Yes, the cat will catch the rat at number 24.

Exercise: Common Multiples | Q: 7 | (Page Page 3)
For More Understanding

Explanation

The cat starts at 6 and jumps 3 steps: positions after n jumps are 6 + 3n. The rat starts at 12 and jumps 2 steps: positions after n jumps are 12 + 2n. Since they jump simultaneously, we need to find when they land on the same number at the same time. Setting the equations equal: 6 + 3n = 12 + 2n. Solving for n gives n = 6. After 6 jumps, the cat will be at 6 + 3(6) = 24 and the rat will be at 12 + 2(6) = 24. Thus, the cat catches the rat at number 24.

Solution Steps

  1. Step 1: Cat starts at 6, jumps 3: positions after n jumps = 6 + 3n

  2. Step 2: Rat starts at 12, jumps 2: positions after n jumps = 12 + 2n

  3. Step 3: Set positions equal to find when they land on the same number at the same time: 6 + 3n = 12 + 2n

  4. Step 4: Solve for n: 3n - 2n = 12 - 6 → n = 6

  5. Step 5: Calculate the position at n = 6: Cat is at 6 + 3(6) = 24, Rat is at 12 + 2(6) = 24

  6. Step 6: Both meet at 24 after 6 jumps, so cat catches rat at 24