A sports store packs 4 shuttlecocks in a bigger box. They have 50 shuttlecocks. How many boxes will they need to pack all of them? Can they pack all the shuttlecocks in the boxes? How many are left?
Given: Total shuttlecocks = 50 Shuttlecocks per box = 4
Calculation: 50 ÷ 4 = 12 boxes with remainder 2
Using partial quotients: 40 shuttlecocks = 10 boxes (50 - 40 = 10 left) 8 shuttlecocks = 2 boxes (10 - 8 = 2 left) Total boxes = 10 + 2 = 12 boxes
Answer: They will need 12 boxes to pack 48 shuttlecocks. 2 shuttlecocks remain unpacked. ∴ They cannot pack all shuttlecocks in the boxes.
Explanation
The chapter presents a division problem with remainder. 50 shuttlecocks ÷ 4 per box = 12 boxes with 2 remaining. Using partial quotients: 40 shuttlecocks = 10 boxes (10 left), 8 shuttlecocks = 2 boxes (2 left). Total boxes = 10 + 2 = 12, with 2 shuttlecocks remaining.
Solution Steps
Step 1: 50 shuttlecocks ÷ 4 per box
Step 2: 40 shuttlecocks = 10 boxes (50-40=10 left)
Step 3: 8 shuttlecocks = 2 boxes (10-8=2 left)
Step 4: Total boxes = 10 + 2 = 12 boxes
Step 5: 2 shuttlecocks remain unpacked