Raksha Bandhan

For each Rakhi we need one flower, ... threads and ... beads. We need to make 5 Rakhis. How many threads, flowers and beads do they need?

For making 10 such Rakhis, we need …… flowers, …… threads and …… beads.

How would we count the laddoos in this box? There are …… laddoos in this box.

After Atya and children come, we will be 9 people in the house. When we distribute 18 laddoos equally to all, how many will each of us get?

Distribute all the 15 pedas in plates equally among 5 people. How many pedas will each get? 15 equally shared by 5 is ... each. 15 ÷ 5 = …

Each cycle needs 2 wheels. How many cycles can be fitted with 12 wheels? 12 equally divided by 2 is .... 12 ÷ 2 = …

At home we are 9 members. Can we have 4 jalebis each? Are there enough jalebis for everyone in Dhara's family to have four each? How many jalebis should Dhara buy so that everyone can get four each?

Dhara: The number of plants is 6 + 6 + 6 + 6 + 6 + 6 = … 8 times 6 = … = $8 \times 6$ = … Gopal: No, it is 8 + 8 + 8 + 8 + 8 + 8 = $6 \times 8$. Who do you think is correct?

Complete the multiplication by 2 pattern: 4 times 2 is …… or $4 \times 2$ = ……, 5 times 2 is …… or $5 \times 2$ = ……, 6 times 2 is …… or $6 \times 2$ = ……, …… times 2 is …… or …… × 2 = ……, …… times …… is …… or $8 \times 2$ = ……, …… times …… is …… or $9 \times 2$ = ……, …… times …… is …… or $10 \times 2$ = ……

Continue the skip jumping pattern: 4 jumps → ..., 5 jumps → ..., 6 jumps → ..., 7 jumps → ..., 8 jumps → ..., 9 jumps → ..., 10 jumps → ...

Guess and write the next number she will jump onto.

Is there a pattern in these numbers: 3, 6, 9, …?

How many steps forward is Dhara jumping each time?

Can this skip jumping be used to form times-6 table? Write times-6 table in your notebook.

What times table can you construct from Gopal's jumps? Make it in your notebook.

Dhara also skip jumps. Gopal notes down the jumps but he misses the first few numbers. 32, 40, 48, 56. By what numbers was Dhara skip jumping? Construct the times table of this number in your notebook.

What skip jumping number will you choose to reach the flower on 12 in the smallest number of jumps? No direct jumping to the flower is allowed.

Are there numbers that can be reached only through skip jumping by 1? Find 3 such numbers.

Look at the times-5 table. What patterns do you see?

Guess what will be the last digits of $11 \times 5$ and $12 \times 5$.