Question 15 of 17intermediate🔧 ApplyShort Answer2 marks

Take the digits 3 and 8 and make as many 2 or 3 digit numbers as you can. You can repeat the digits.

Correct Answer

Step 1: For 2-digit numbers, each place can be 3 or 8. Step 2: 2-digit combinations: 33, 38, 83, 88 (4 numbers).

Step 3: For 3-digit numbers, each place can be 3 or 8. Step 4: 3-digit combinations: 333, 338, 383, 388, 833, 838, 883, 888 (8 numbers).

Answer: Total 12 numbers can be made using digits 3 and 8 with repetition allowed.

Exercise: My numbers | Q: 1 | (Page Page 10)
For More Understanding

Explanation

With digits 3 and 8, allowing repetition, we can make: 2-digit numbers (33, 38, 83, 88) and 3-digit numbers (333, 338, 383, 388, 833, 838, 883, 888). Children systematically list all possible combinations.

Solution Steps

  1. Step 1: For 2-digit numbers, each place can be 3 or 8

  2. Step 2: 2-digit combinations: 33, 38, 83, 88 (4 numbers)

  3. Step 3: For 3-digit numbers, each place can be 3 or 8

  4. Step 4: 3-digit combinations: 333, 338, 383, 388, 833, 838, 883, 888 (8 numbers)

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