Question 13 of 24intermediate🔧 ApplyNumerical3 marks

(a) A giant refracting telescope at an observatory has an objective lens of focal length 15m. If an eyepiece of focal length 1.0cm is used, what is the angular magnification of the telescope? (b) If this telescope is used to view the moon, what is the diameter of the image of the moon formed by the objective lens? The diameter of the moon is 3.48×3.48 \times 10^{6} m, and the radius of lunar orbit is 3.8×3.8 \times 10^{8}$$ m.

(a)
Answer

The angular magnification of the telescope is 1500.

(b)
Answer

The diameter of the image of the moon formed by the objective lens is 13.74 cm (or 0.137 m).

Explanation

Part (a) uses the standard telescope magnification formula m = f₀/fₑ. Part (b) requires understanding that for distant objects, the image is formed at the focal plane of the objective lens. The angle subtended by the moon at the objective equals the angle subtended by the image at the objective, allowing us to calculate the image size using similar triangles.