Question 3 of 8beginner🔧 ApplyNumerical2 marks

A radio can tune in to any station in the 7.5 MHz to 12 MHz band. What is the corresponding wavelength band?

Correct Answer

The corresponding wavelength band is 25 m to 40 m.

The relationship between wavelength (λ) and frequency (ν) for electromagnetic waves is given by λ = c/ν, where c = 3×103 \times 10⁸ m/s is the speed of light in vacuum. All electromagnetic waves travel through vacuum with the same speed.

Step 1: Calculate wavelength for lower frequency (7.5 MHz) ν₁ = 7.5 MHz = 7.5×107.5 \times 10⁶ Hz λ₁ = c/ν₁ = (3×103 \times 10⁸)/(7.5×107.5 \times 10⁶) = 40 m

Step 2: Calculate wavelength for higher frequency (12 MHz) ν₂ = 12 MHz = 12×1012 \times 10⁶ Hz λ₂ = c/ν₂ = (3×103 \times 10⁸)/(12×1012 \times 10⁶) = 25 m

Since higher frequency corresponds to shorter wavelength, the wavelength band extends from 25 m to 40 m. This falls within the radio wave range (wavelength > 0.1 m).

Exercise: EXERCISES | Q: 8.5
For More Understanding

Explanation

This question tests the student's understanding of the inverse relationship between wavelength and frequency for electromagnetic waves. The context establishes that all electromagnetic waves travel through vacuum with the same speed (c = 3×103 \times 10⁸ m/s), and the basic difference between various types lies in their wavelengths or frequencies. The formula λ = c/ν is fundamental. Students must recognize that lower frequency (7.5 MHz) gives longer wavelength (40 m), and higher frequency (12 MHz) gives shorter wavelength (25 m). The calculated wavelengths fall within the radio wave category mentioned in the context (wavelength > 0.1 m).

Solution Steps

  1. Step 1: Convert frequencies from MHz to Hz: 7.5 MHz = 7.5×107.5 \times 10⁶ Hz and 12 MHz = 12×1012 \times 10⁶ Hz

  2. Step 2: Apply the formula λ = c/ν where c = 3×103 \times 10⁸ m/s

  3. Step 3: Calculate λ₁ = (3×103 \times 10⁸)/(7.5×107.5 \times 10⁶) = 40 m for the lower frequency

  4. Step 4: Calculate λ₂ = (3×103 \times 10⁸)/(12×1012 \times 10⁶) = 25 m for the higher frequency

  5. Step 5: State the wavelength band as 25 m to 40 m (shorter wavelength corresponds to higher frequency)