Question 47 of 68intermediate🔧 ApplyNumerical4 marks

Find the area of the parallelogram whose adjacent sides are determined by the vectors a⃗ = î - ĵ + 3k̂ and b⃗ = 2î - 7ĵ + k̂.

Correct Answer

The area of the parallelogram is 152\sqrt{2} square units.

Exercise: EXERCISE 10.4 | Q: 10 | (Page 32)
For More Understanding

Explanation

This question is from Exercise 10.4 and tests the concept that the area of a parallelogram with adjacent sides represented by vectors a⃗ and b⃗ is given by |a⃗ × b⃗|. The solution requires computing the cross product using determinant method and then finding its magnitude.

Solution Steps

  1. Step 1: The area of a parallelogram with adjacent sides a⃗ and b⃗ is given by |a⃗ × b⃗|.

  2. Step 2: Compute the cross product a⃗ × b⃗ = |î ĵ k̂; 1 -1 3; 2 -7 1|

  3. Step 3: Expanding the determinant: î[(-1)(1) - (3)(-7)] - ĵ[(1)(1) - (3)(2)] + k̂[(1)(-7) - (-1)(2)]

  4. Step 4: Simplifying: î(-1 + 21) - ĵ(1 - 6) + k̂(-7 + 2) = 20î + 5ĵ - 5k̂

  5. Step 5: Find magnitude: |a⃗ × b⃗| = 202+52+(−5\sqrt{20² + 5² + (-5}²) = 400+25+25\sqrt{400 + 25 + 25} = 450\sqrt{450} = 152\sqrt{2}