Question 26 of 68intermediate🔧 ApplyNumerical2 marks

Find |a⃗| and |b⃗|, if (a⃗ + b⃗) ⋅ (a⃗ - b⃗) = 8 and |a⃗| = 8 |b⃗|.

Correct Answer

|a⃗| = 1614\sqrt{14}/21 and |b⃗| = 214\sqrt{14}/21

Exercise: EXERCISE 10.3 | Q: 6 | (Page 25)
For More Understanding

Explanation

This question tests the property of dot product expansion. Following the pattern shown in Example 17 and Example 18 from the textbook, we expand (a⃗ + b⃗) ⋅ (a⃗ - b⃗) using the distributive property. The key insight is that this simplifies to |a⃗|² - |b⃗|², which creates a system of equations when combined with the given relationship |a⃗| = 8|b⃗|.

Solution Steps

  1. Step 1: Expand the dot product: (a⃗ + b⃗) ⋅ (a⃗ - b⃗) = a⃗ ⋅ a⃗ - a⃗ ⋅ b⃗ + b⃗ ⋅ a⃗ - b⃗ ⋅ b⃗ = |a⃗|² - |b⃗|²

  2. Step 2: Given that (a⃗ + b⃗) ⋅ (a⃗ - b⃗) = 8, we get: |a⃗|² - |b⃗|² = 8

  3. Step 3: Given |a⃗| = 8|b⃗|, let |b⃗| = x, then |a⃗| = 8x

  4. Step 4: Substitute into the equation: (8x)² - x² = 8

  5. Step 5: Simplify: 64x² - x² = 8 → 63x² = 8 → x² = 8/63

  6. Step 6: Solve: x = 8/63\sqrt{8/63} = 214\sqrt{14}/21

  7. Step 7: Therefore, |b⃗| = 214\sqrt{14}/21 and |a⃗| = $$8 \times 2$$$\sqrt{14}/21=16/21 = 16\sqrt{14}$/21