Question 22 of 33intermediate🔧 ApplyShort Answer3 marks

The function 't' which maps temperature in degree Celsius into temperature in degree Fahrenheit is defined by t(C)=9C5+32t(C) = \frac{9C}{5} + 32. Find

(i)

t(0)t(0)

Answer

32

(ii)

t(28)t(28)

Answer

82.4

(iii)

t(−10)t(-10)

Answer

14

(iv)

The value of CC, when t(C)=212t(C) = 212.

Answer

100

Explanation

This question tests the evaluation of a function at specific points and finding the input for a specific output, based on the function definition provided in Exercise 2.3 of the textbook. Parts (i), (ii), and (iii) require direct substitution of the Celsius value into the function rule, similar to the method used in Question 3 of the same exercise. Part (iv) requires setting the function equal to 212 and solving the resulting linear equation for C, a process consistent with solving linear functions described in the 'Miscellaneous Examples' and section 2.4.1.