Question 63 of 96intermediate🔍 AnalyzeMCQ1 mark

Which of the following is a homogeneous differential equation?

Exercise: EXERCISE 9.4 | Q: 17 | (Page 23)
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Explanation

A differential equation of the form dy/dx = F(x, y) is said to be homogeneous if F(x, y) is a homogeneous function of degree zero. This means when we replace x by λx and y by λy, we should get F(λx, λy) = λ⁰F(x, y) = F(x, y). Let me analyze each option:

Option (A): The equation has constant terms (5 and 4), so it's NOT homogeneous.

Option (B): Rearranging gives dy/dx = xy/(x³ + y³). Here numerator has degree 2, denominator has degree 3, so overall degree is -1 ≠\neq 0. NOT homogeneous.

Option (C): Rearranging gives dy/dx = -(x³ + 2y²)/(2xy). The terms in numerator have different degrees (x³ has degree 3, y² has degree 2). NOT homogeneous.

Option (D): Rearranging gives dy/dx = y²/(x² - xy - y²). All terms have degree 2. F(λx, λy) = λ²y²/[λ²(x² - xy - y²)] = λ⁰F(x, y). This IS a homogeneous differential equation.

Solution Steps

  1. Step 1: Recall that a homogeneous differential equation has F(x,y) as a homogeneous function of degree zero.

  2. Step 2: For each option, express in the form dy/dx = F(x,y) and check if F(λx, λy) = λ⁰F(x,y).

  3. Step 3: Option (D): y² dx + (x² - xy - y²) dy = 0 gives dy/dx = y²/(x² - xy - y²).

  4. Step 4: Verify: F(λx, λy) = λ²y²/[λ²(x² - xy - y²)] = λ⁰F(x, y). Hence homogeneous.

  5. Step 5: Options (A), (B), (C) do not satisfy the homogeneous condition.