Question 12 of 96beginner💡 UnderstandMCQ1 mark

The order of the differential equation

2x2d2ydx2−3dydx+y=02x^2 \frac{d^2 y}{dx^2} - 3 \frac{dy}{dx} + y = 0
Exercise: EXERCISE 9.1 | Q: 12 | (Page 5)
For More Understanding

Explanation

According to the textbook, the order of a differential equation is defined as the order of the highest order derivative of the dependent variable with respect to the independent variable involved in the given differential equation. In the given equation 2x2d2ydx2−3dydx+y=02x^2 \frac{d^2 y}{dx^2} - 3 \frac{dy}{dx} + y = 0, the derivatives present are d2ydx2\frac{d^2 y}{dx^2} (second order) and dydx\frac{dy}{dx} (first order). The highest order derivative is d2ydx2\frac{d^2 y}{dx^2}, which is of order 2. Therefore, the order of the given differential equation is 2.

Solution Steps

  1. Step 1: Identify all derivatives in the given differential equation: d2ydx2\frac{d^2 y}{dx^2} and dydx\frac{dy}{dx}.

  2. Step 2: Determine the highest order derivative present, which is d2ydx2\frac{d^2 y}{dx^2} (second order derivative).

  3. Step 3: Apply the definition: Order of a differential equation is the order of the highest order derivative involved.

  4. Step 4: Conclude that the order is 2, so option (A) is correct.