Question 7 of 96beginner💡 UnderstandVery Short1 mark

Determine order and degree (if defined) of differential equations given in Exercises 1 to 10.

y′′+2y′′+y′=0y'' + 2y'' + y' = 0
Correct Answer

Order = 3, Degree = 1

Exercise: EXERCISE 9.1 | Q: 7 | (Page 4)
For More Understanding

Explanation

The highest order derivative present in the equation y′′′+2y′′+y′=0y''' + 2y'' + y' = 0 is y′′′y''', which is the third-order derivative. Thus, the order is 3. The equation is a polynomial in its derivatives, and the highest power of the highest order derivative is 1, making the degree 1.

Solution Steps

  1. Step 1: Identify the highest order derivative in the equation y′′′+2y′′+y′=0y''' + 2y'' + y' = 0. The term with the highest derivative is y′′′y'''.

  2. Step 2: Determine the order. The derivative y′′′y''' is the third-order derivative. Therefore, the order is 3.

  3. Step 3: Check if the equation is a polynomial in derivatives. The equation involves derivatives with integer powers, so it is a polynomial equation.

  4. Step 4: Determine the degree. The highest power of the highest order derivative (y′′′y''') is 1. Thus, the degree is 1.