Question 6 of 82beginner🔧 ApplyNumerical2 marks

The radius of a circle is increasing at the rate of 0.7 cm/s. What is the rate of increase of its circumference?

Correct Answer

The rate of increase of the circumference is 1.4π cm/s.

Exercise: EXERCISE 6.1 | Q: 6 | (Page 5)
For More Understanding

Explanation

This question tests the application of derivatives in related rates, similar to Example 3 and Example 35 in the provided context. While those examples calculate the rate of change of area (dA/dtdA/dt), this question requires calculating the rate of change of circumference (dC/dtdC/dt). The key insight from the context is the application of the Chain Rule: dy/dt=(dy/dx)⋅(dx/dt)dy/dt = (dy/dx) \cdot (dx/dt). Since the circumference formula C=2πrC = 2\pi r is linear with respect to rr, the rate of change is constant and does not depend on the specific radius value at a given instant, unlike the area calculation.

Solution Steps

  1. Step 1: Let rr be the radius and CC be the circumference of the circle. The formula for circumference is C=2πrC = 2\pi r.

  2. Step 2: To find the rate of increase of circumference, differentiate CC with respect to time tt. Using the Chain Rule shown in the context: dCdt=ddr(2πr)⋅drdt=2πdrdt\frac{dC}{dt} = \frac{d}{dr}(2\pi r) \cdot \frac{dr}{dt} = 2\pi \frac{dr}{dt}

  3. Step 3: Given the rate of increase of radius is drdt=0.7 cm/s\frac{dr}{dt} = 0.7 \text{ cm/s}. Substitute this value into the equation: dCdt=2π(0.7)=1.4π cm/s\frac{dC}{dt} = 2\pi (0.7) = 1.4\pi \text{ cm/s}