Question 40 of 82intermediate🔧 ApplyLong Answer6 marks

Find the local maxima and local minima, if any, of the following functions. Find also the local maximum and the local minimum values, as the case may be:

(i)

f(x) = x²

Answer

Point of local minimum: x = 0; Local minimum value = 0; No local maximum.

(ii)

g(x) = x³ - 3x

Answer

Point of local maximum: x = -1, Local maximum value = 2; Point of local minimum: x = 1, Local minimum value = -2.

(iii)

h(x) = sin x + cos x, 0 < x < π/2

Answer

Point of local maximum: x = π/4; Local maximum value = 2\sqrt{2}; No local minimum.

(iv)

f(x) = sin x - cos x, 0 < x < 2π

Answer

Point of local maximum: x = 3π/4, Local maximum value = 2\sqrt{2}; Point of local minimum: x = 7π/4, Local minimum value = -2\sqrt{2}.

(v)

f(x) = x³ - 6x² + 9x + 15

Answer

Point of local maximum: x = 1, Local maximum value = 19; Point of local minimum: x = 3, Local minimum value = 15.

(vi)

g(x) = x/2 + 2/x, x > 0

Answer

Point of local minimum: x = 2; Local minimum value = 2; No local maximum.

(vii)

g(x) = 1/(x² + 2)

Answer

Point of local maximum: x = 0; Local maximum value = 1/2; No local minimum.

(viii)

f(x) = x1−x\sqrt{1-x}, 0 < x < 1

Answer

Point of local maximum: x = 2/3; Local maximum value = 23\sqrt{3}/9; No local minimum.

Explanation

This question tests the application of first and second derivative tests to find local maxima and minima. For each function, we find critical points where f'(x) = 0, then use the second derivative test: if f''(c) > 0, it's a local minimum; if f''(c) < 0, it's a local maximum. The textbook context in Example 17 demonstrates this method for polynomial functions, and Definition 4 provides the theoretical foundation for identifying points of local maxima/minima.