Question 9 of 44intermediate💡 UnderstandShort Answer2 marks

Why are Mn2+Mn^{2+} compounds more stable than Fe2+Fe^{2+} towards oxidation to their +3 state?

Correct Answer

Mn2+Mn^{2+} has a d5d^{5} half-filled configuration which is particularly stable due to maximum exchange energy. This makes it difficult to remove an electron from Mn2+Mn^{2+}, giving it a high third ionisation enthalpy. Hence, Mn2+Mn^{2+} resists oxidation to Mn3+Mn^{3+}.

In contrast, Fe2+Fe^{2+} has a d6d^{6} configuration. Upon oxidation to Fe3+Fe^{3+}, it attains a stable d5d^{5} half-filled configuration. The third ionisation enthalpy of Fe is lower than that of Mn, making Fe2+Fe^{2+} more easily oxidized to Fe3+Fe^{3+}.

Thus, Mn2+Mn^{2+} compounds are more stable than Fe2+Fe^{2+} towards oxidation to their +3 state.

Exercise: EXERCISES | Q: 4.2 | (Page 27)
For More Understanding

Explanation

The textbook explains this in section 4.3.6 discussing trends in M3+M^{3+}/M2+M^{2+} standard electrode potentials. The key concept is that half-filled d5d^{5} configurations have extra stability due to exchange energy (explained in the context about Hund's rule and parallel spins). Mn2+Mn^{2+} already has this stable d5d^{5} configuration, so it resists losing an electron. Fe2+Fe^{2+} (d6d^{6}) readily loses an electron to achieve the stable d5d^{5} configuration as Fe3+Fe^{3+}. The context explicitly states that 'the third ionisation enthalpy of Fe is lower than that of Mn' and that 'Mn2+Mn^{2+}(d5d^{5}) is particularly stable' while 'Fe3+Fe^{3+}(d5d^{5})' has extra stability.