If the density of some lake water is 1.25g mL-1 and contains 92 g of Na+ ions per kg of water, calculate the molarity of Na+ ions in the lake.
The molarity of Na⁺ ions in the lake water is 4.58 M.
Explanation
This question tests the concept of molarity calculation. Molarity is defined as the number of moles of solute dissolved in one litre of solution. The key steps involve: (1) calculating moles of Na⁺ ions from the given mass, (2) determining the total mass of solution (water + Na⁺ ions), (3) converting mass to volume using density, and (4) applying the molarity formula. Students must remember that the volume is of the solution, not just the solvent.
Solution Steps
Step 1: Calculate moles of Na⁺ ions Moles of Na⁺ = Mass / Molar mass = 92 g / 23 g mol⁻¹ = 4 mol
Step 2: Calculate total mass of solution Mass of water = 1 kg = 1000 g Mass of Na⁺ ions = 92 g Total mass of solution = 1000 g + 92 g = 1092 g
Step 3: Calculate volume of solution Volume = Mass / Density = 1092 g / 1.25 g mL⁻¹ = 873.6 mL = 0.8736 L
Step 4: Calculate molarity Molarity = Moles of solute / Volume of solution in litre Molarity = 4 mol / 0.8736 L = 4.58 mol L⁻¹ or 4.58 M