Calculate the mole fraction of benzene in solution containing 30% by mass in carbon tetrachloride.
Mole fraction of benzene = 0.458
Explanation
This is a straightforward mole fraction calculation. The key steps involve: (1) interpreting 30% by mass correctly, (2) calculating molar masses of both components, (3) finding moles of each component, and (4) applying the mole fraction formula. The context shows similar calculations in other examples where moles are calculated by dividing mass by molar mass, and mole fraction is found by dividing moles of one component by total moles.
Solution Steps
Step 1: 30% by mass benzene means 30 g benzene and 70 g CCl₄ in 100 g solution.
Step 2: Molar mass of benzene (C₆H₆) = + = 78 g mol⁻¹
Step 3: Molar mass of CCl₄ = 12 + = 154 g mol⁻¹
Step 4: Moles of benzene = 30 g / 78 g mol⁻¹ = 0.385 mol
Step 5: Moles of CCl₄ = 70 g / 154 g mol⁻¹ = 0.455 mol
Step 6: Total moles = 0.385 + 0.455 = 0.840 mol
Step 7: Mole fraction of benzene = 0.385 / 0.840 = 0.458