Question 11 of 26intermediate🔧 ApplyShort Answer2 marks

Write the isomers of the compound having formula C₄H₉Br.

Correct Answer

The compound C₄H₉Br has four structural isomers:

1. 1-Bromobutane (Primary bromide) CH₃CH₂CH₂CH₂Br

2. 2-Bromobutane (Secondary bromide) CH₃CH₂CHBrCH₃

3. 1-Bromo-2-methylpropane (Primary bromide) (CH₃)₂CHCH₂Br

4. 2-Bromo-2-methylpropane (Tertiary bromide) (CH₃)₃CBr

Exercise: EXERCISES | Q: 6.6 | (Page 31)
For More Understanding

Explanation

The question asks for structural isomers of C₄H₉Br. Following the pattern shown in Example 6.1 of the textbook (which demonstrates 8 isomers for C₅H₁₁Br), students should identify that C₄H₉Br is derived from butane (C₄H₁₀). Butane has two structural isomers (n-butane and isobutane), and each can form different monobromo derivatives based on the position of bromine substitution. n-Butane gives 2 isomers (1° and 2°), while isobutane gives 2 isomers (1° and 3°), totaling 4 structural isomers.

Solution Steps

  1. Step 1: Identify the parent alkane as butane (C₄H₁₀)

  2. Step 2: Determine possible carbon skeletons: n-butane (straight chain) and isobutane (branched)

  3. Step 3: For n-butane, bromine can substitute at position 1 (primary) or position 2 (secondary)

  4. Step 4: For isobutane, bromine can substitute at position 1 (primary) or position 2 (tertiary)

  5. Step 5: Write all four isomers with their IUPAC names and classify as primary, secondary, or tertiary bromides

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