Question 24 of 29intermediate🔧 ApplyNumerical3 marks
How much charge is required for the following reductions: (i) 1 mol of Al³⁺ to Al? (ii) 1 mol of Cu²⁺ to Cu? (iii) 1 mol of MnO₄⁻ to Mn²⁺?
(i)
Answer
289500 C (or 3F)
(ii)
Answer
193000 C (or 2F)
(iii)
Answer
482500 C (or 5F)
Explanation
The question requires calculating charge using Faraday's constant. From the context, 1 Faraday (F) = 96500 C mol⁻¹, which is the charge on 1 mole of electrons. For each reduction, we need to determine the number of electrons involved in the reaction, then multiply by Faraday's constant.