Question 31 of 34beginner🔧 ApplyMCQ1 mark

How many ions are produced from the complex [Co(NH3)6Cl2] in solution?

Exercise: EXERCISES | Q: 5.28 | (Page Page 22)
For More Understanding

Explanation

According to the context, 'the atoms within the square brackets form a single entity which does not dissociate under the reaction conditions.' The complex [Co(NH₃)₆Cl₂] should be interpreted as [Co(NH₃)₆]Cl₂, where [Co(NH₃)₆]²⁺ is the complex ion (coordination number 6) and 2 Cl⁻ are counter ions outside the coordination sphere. In solution, this produces 3 ions total: 1 complex ion [Co(NH₃)₆]²⁺ and 2 chloride ions Cl⁻. This follows the pattern shown in Table 5.1, where complexes like [CoCl₂(NH₃)₄]⁺Cl⁻ produce 2 ions (1:1 electrolyte), [CoCl(NH₃)₅]²⁺2Cl⁻ produce 3 ions (1:2 electrolyte), and [Co(NH₃)₆]³⁺3Cl⁻ produce 4 ions (1:3 electrolyte).

Solution Steps

  1. Step 1: Identify the coordination sphere - atoms within square brackets [Co(NH₃)₆] form one entity that does not dissociate.

  2. Step 2: Identify counter ions outside the coordination sphere - 2 Cl⁻ ions are counter ions.

  3. Step 3: Count total ions produced in solution - 1 complex ion [Co(NH₃)₆]²⁺ + 2 Cl⁻ = 3 ions total.