Question 23 of 37intermediate🔧 ApplyNumerical3 marks

The half-life for radioactive decay of 14C^{14}\text{C} is 5730 years. An archaeological artifact containing wood had only 80% of the 14C^{14}\text{C} found in a living tree. Estimate the age of the sample.

Correct Answer

Radioactive decay is a first-order reaction. To estimate the age of the sample, we use the integrated rate law equation.

Step 1: Calculate the rate constant (kk). For a first-order reaction, the relationship between half-life and rate constant is given by:

t1/2=0.693kt_{1/2} = \frac{0.693}{k}

Given t1/2=5730t_{1/2} = 5730 years.

k=0.6935730=1.21×10−4 year−1k = \frac{0.693}{5730} = 1.21 \times 10^{-4} \text{ year}^{-1}

Step 2: Use the integrated rate law. The integrated rate law for a first-order reaction is:

t=2.303klog⁡[R]0[R]t = \frac{2.303}{k} \log \frac{[R]_0}{[R]}

Given that the artifact has 80% of the 14C^{14}\text{C} found in a living tree, we can assume the initial concentration [R]0=100[R]_0 = 100 and the final concentration [R]=80[R] = 80.

Step 3: Calculate the age (tt). Substituting the values into the equation:

t=2.3031.21×10−4log⁡(10080)t = \frac{2.303}{1.21 \times 10^{-4}} \log \left(\frac{100}{80}\right) t=2.3031.21×10−4log⁡(1.25)t = \frac{2.303}{1.21 \times 10^{-4}} \log (1.25) t=2.3031.21×10−4(0.0969)t = \frac{2.303}{1.21 \times 10^{-4}} (0.0969) t=1845 yearst = 1845 \text{ years}

The estimated age of the sample is 1845 years.

Exercise: EXERCISES | Q: 3.14 | (Page 26)
For More Understanding

Explanation

This question applies the concept of first-order kinetics to radioactive dating. The context provides the formula for the half-life of a first-order reaction (t1/2=0.693/kt_{1/2} = 0.693/k) and the integrated rate law (k=2.303tlog⁡[R]0[R]k = \frac{2.303}{t} \log \frac{[R]_0}{[R]}). By calculating the rate constant from the half-life and substituting the ratio of remaining Carbon-14 into the integrated rate equation, the age of the artifact is determined.

Solution Steps

  1. Step 1: Calculate the rate constant (kk) using the half-life formula k=0.693t1/2k = \frac{0.693}{t_{1/2}}.

  2. Step 2: Set up the integrated rate law equation t=2.303klog⁡[R]0[R]t = \frac{2.303}{k} \log \frac{[R]_0}{[R]}.

  3. Step 3: Substitute [R]0=100[R]_0 = 100, [R]=80[R] = 80, and the calculated kk value to solve for time tt.