Question 18 of 20intermediate🔧 ApplyShort Answer3 marks

Complete the following reactions: (i) C₆H₅NH₂ + CHCl₃ + alc.KOH → (ii) C₆H₅N₂Cl + H₃PO₂ + H₂O → (iii) C₆H₅NH₂ + H₂SO₄ (conc.) → (iv) C₆H₅N₂Cl + C₂H₅OH → (v) C₆H₅NH₂ + Br₂ (aq) → (vi) C₆H₅NH₂ + (CH₃CO)₂ O → (vii) C₆H₅N₂Cl →[(i)HBF₄] [(ii) NaNO₂/Cu, Δ]

(i)
Answer

C₆H₅NC + KCl + H₂O (Phenyl isocyanide)

(ii)
Answer

C₆H₆ + N₂ + H₃PO₃ + HCl (Benzene)

(iii)
Answer

C₆H₅NH₃⁺HSO₄⁻ (Anilinium hydrogen sulfate)

(iv)
Answer

C₆H₅OC₂H₅ + N₂ + HCl (Phenetole/Ethoxybenzene)

(v)
Answer

2,4,6-Tribromoaniline

(vi)
Answer

C₆H₅NHCOCH₃ + CH₃COOH (Acetanilide)

(vii)
Answer

C₆H₅NO₂ (Nitrobenzene)

Explanation

Question 9.11 from NCERT tests key reactions of aromatic amines and diazonium salts. (i) Carbylamine reaction produces phenyl isocyanide. (ii) Diazonium salts reduced by H₃PO₂ yield benzene. (iii) Aniline forms salt with conc. H₂SO₄. (iv) Diazonium salt with ethanol gives phenetole. (v) Aniline bromination gives 2,4,6-tribromoaniline due to strong activation. (vi) Acetylation yields acetanilide. (vii) Diazonium fluoroborate with NaNO₂/Cu gives nitrobenzene.

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