Question 26 of 26advanced🔧 ApplyLong Answer5 marks

Write structural formulas and names of four possible aldol condensation products from propanal and butanal. In each case, indicate which aldehyde acts as nucleophile and which as electrophile.

Correct Answer

Product 1: Self-condensation of Propanal

Structural formula: CH₃-CH₂-C(CH₃)=CH-CHO Name: 2-Methylpent-2-enal Nucleophile: Propanal (forms enolate ion) Electrophile: Propanal (carbonyl carbon)

Product 2: Self-condensation of Butanal

Structural formula: CH₃-CH₂-CH₂-C(CH₂CH₃)=CH-CHO Name: 2-Ethylhex-2-enal Nucleophile: Butanal (forms enolate ion) Electrophile: Butanal (carbonyl carbon)

Product 3: Cross aldol (Propanal as nucleophile, Butanal as electrophile)

Structural formula: CH₃-CH₂-CH₂-C(CH₃)=CH-CHO Name: 2-Methylhex-2-enal Nucleophile: Propanal (forms enolate ion) Electrophile: Butanal (carbonyl carbon)

Product 4: Cross aldol (Butanal as nucleophile, Propanal as electrophile)

Structural formula: CH₃-CH₂-C(CH₂CH₃)=CH-CHO Name: 2-Ethylpent-2-enal Nucleophile: Butanal (forms enolate ion) Electrophile: Propanal (carbonyl carbon)

Exercise: EXERCISES | Q: 8.9 | (Chapter: 30)
For More Understanding

Explanation

According to the textbook context, when cross aldol condensation is carried out between two different aldehydes both containing α-hydrogen atoms, it gives a mixture of four products. Both propanal (CH₃CH₂CHO) and butanal (CH₃CH₂CH₂CHO) have α-hydrogens, so each can act as both nucleophile (by forming enolate ion) and electrophile (through its carbonyl carbon). The four products arise from: (1) two molecules of propanal reacting, (2) two molecules of butanal reacting, (3) propanal enolate attacking butanal, and (4) butanal enolate attacking propanal. The aldol products initially formed are β-hydroxy aldehydes, which undergo dehydration to give α,β-unsaturated aldehydes (aldol condensation products).

Solution Steps

  1. Step 1: Identify that both propanal and butanal contain α-hydrogens, so both can form enolate ions and act as electrophiles.

  2. Step 2: Write the self-condensation products: propanal with propanal gives 2-methylpent-2-enal; butanal with butanal gives 2-ethylhex-2-enal.

  3. Step 3: Write the cross aldol products: propanal enolate attacking butanal gives 2-methylhex-2-enal; butanal enolate attacking propanal gives 2-ethylpent-2-enal.

  4. Step 4: For each product, identify which aldehyde provided the enolate (nucleophile) and which provided the carbonyl carbon (electrophile).