Question 20 of 39intermediate🔧 ApplyShort Answer3 marks

You are given benzene, conc. H₂SO₄ and NaOH. Write the equations for the preparation of phenol using these reagents.

Correct Answer

Phenol can be prepared from benzene, conc. H₂SO₄ and NaOH through the benzenesulphonic acid method.

Step 1: Sulphonation of benzene Benzene is sulphonated with conc. H₂SO₄ to form benzene sulphonic acid.

C6H6+H2SO4→C6H5SO3H\text{C}_6\text{H}_6 + \text{H}_2\text{SO}_4 \rightarrow \text{C}_6\text{H}_5\text{SO}_3\text{H}

Step 2: Fusion with molten NaOH Benzene sulphonic acid is converted to sodium phenoxide on heating with molten sodium hydroxide.

C6H5SO3H+NaOH→heatC6H5ONa\text{C}_6\text{H}_5\text{SO}_3\text{H} + \text{NaOH} \xrightarrow{\text{heat}} \text{C}_6\text{H}_5\text{ONa}

Step 3: Acidification Acidification of sodium phenoxide gives phenol.

C6H5ONa→H+C6H5OH\text{C}_6\text{H}_5\text{ONa} \xrightarrow{\text{H}^+} \text{C}_6\text{H}_5\text{OH}
Exercise: EXERCISES | Q: 7.12 | (Page Page 30)
For More Understanding

Explanation

The question specifically asks for preparation of phenol using benzene, conc. H₂SO₄ and NaOH. According to the textbook context under 'From benzenesulphonic acid', benzene is first sulphonated with oleum (or conc. H₂SO₄) to form benzene sulphonic acid, which is then heated with molten NaOH to form sodium phenoxide. Finally, acidification yields phenol. This is a three-step process involving sulphonation, alkali fusion, and acidification.

Solution Steps

  1. Step 1: Sulphonation - Benzene reacts with conc. H₂SO₄ to form benzene sulphonic acid

  2. Step 2: Alkali fusion - Benzene sulphonic acid heated with molten NaOH gives sodium phenoxide

  3. Step 3: Acidification - Sodium phenoxide is acidified to obtain phenol