Question 9 of 39intermediate🔧 ApplyShort Answer3 marks

Write IUPAC names of the following compounds: (i) CH₃–CH(OH)–CH(CH₃)–C(CH₃)₂–CH₃ (ii) H₃C–CH(OH)–CH₂–CH(OH)–CH₂–CH₃ (iii) CH₃–CH(OH)–CH(OH)–CH₃ (iv) HO–CH₂–CH(OH)–CH₂–OH (v) CH₃–O–CH₂–CH(CH₃)–CH₃ (x) C₆H₅–O–C₂H₅ (xi) C₆H₅–O–C₇H₁₅(n-) (xii) CH₃–CH₂–O–CH(CH₃)–CH₂–CH₃

(i)
Answer

3,4,4-Trimethylpentan-2-ol

(ii)
Answer

Hexane-2,4-diol

(iii)
Answer

Butane-2,3-diol

(iv)
Answer

Propane-1,2,3-triol

(v)
Answer

1-Methoxy-2-methylpropane

(x)
Answer

Ethoxybenzene

(xi)
Answer

Heptyloxybenzene

(xii)
Answer

2-Ethoxybutane

Explanation

For alcohols (i-iv), identify the longest carbon chain containing the -OH group, number from the end nearest to -OH, and name substituents alphabetically. For compound (i), the parent chain is pentane with -OH at C-2, one methyl at C-3, and two methyls at C-4. For diols and triols, indicate all -OH positions. For ethers (v, x, xi, xii), the larger alkyl/aryl group becomes the parent hydrocarbon and the smaller group becomes the alkoxy substituent. For aryl-alkyl ethers like (x) and (xi), the aryl group (benzene) is the parent. In compound (v), the larger group is 2-methylpropyl, giving 1-methoxy-2-methylpropane. In (xii), the larger group is butyl, giving 2-ethoxybutane.

PreviousNext