When would you say that the resolution has been passed with 'special majority' in this situation?
For a resolution to be passed with special majority, it must fulfill two conditions: first, it requires two-thirds majority of those present and voting; second, it requires a simple majority of the total membership of the House.
In the given situation, the class has a total strength of 57 students. On the day of voting, 51 students are present and 50 students participate in voting. To pass the resolution with special majority, it must secure two-thirds of 50, which equals 34 votes (since /3 = 33.33, rounded up to 34). Additionally, it must also secure a simple majority of 57, which is 29 votes (more than half). Since 34 votes is the higher requirement, the resolution would be passed with special majority if it secures at least 34 votes.
Explanation
The textbook clearly defines special majority as requiring both conditions to be met simultaneously. The question tests the student's ability to apply this definition to a numerical situation. The key insight is that both conditions must be satisfied - the two-thirds of those present and voting (34 votes) AND simple majority of total membership (29 votes). Since 34 > 29, the higher threshold of 34 votes automatically satisfies both conditions. This is a practical application question that helps students understand how special majority works in real scenarios like impeachment of the President.
Solution Steps
Step 1: Calculate two-thirds of those present and voting: /3 = 33.33 34 votes required
Step 2: Calculate simple majority of total membership: 57 ÷ 2 = 28.5, so 29 votes required
Step 3: Compare both requirements - since 34 > 29, the resolution needs at least 34 votes to pass with special majority