Question 10 of 23intermediate💡 UnderstandShort Answer3 marks

Use the formula v=γPρv = \sqrt{\frac{\gamma P}{\rho}} to explain why the speed of sound in air

(a)

is independent of pressure,

Answer

From the formula v=γPρv = \sqrt{\frac{\gamma P}{\rho}}, for an ideal gas at constant temperature, pressure P and density ρ are directly proportional to each other. When pressure changes, density changes proportionally, keeping the ratio P/ρ constant. Hence, the speed of sound is independent of pressure.

(b)

increases with temperature,

Answer

At higher temperatures, the gas expands and its density ρ decreases. Since velocity v is inversely proportional to the square root of density (v ∝ 1/√ρ) from the formula, a decrease in density causes an increase in velocity. Thus, the speed of sound increases with temperature.

(c)

increases with humidity.

Answer

Humid air contains water vapour which has lower molecular mass than dry air components. This results in lower density ρ for humid air compared to dry air. Since v ∝ 1/√ρ from the formula, lower density leads to higher speed. Therefore, the speed of sound increases with humidity.

Explanation

The question requires explaining three properties of sound speed using the Laplace formula v = γP/ρ\sqrt{γP/ρ}. For (a), the key insight is that P/ρ remains constant at constant temperature due to ideal gas behavior - both change proportionally. For (b), temperature affects density inversely - higher T means lower ρ, hence higher v. For (c), humidity introduces lighter water vapour molecules (molecular mass 18 vs ~29 for air), reducing overall density and increasing speed. The context provides the Laplace formula and confirms that for air γ = 7/5.