Question 17 of 23advanced🔧 ApplyNumerical5 marks

The transverse displacement of a string (clamped at its both ends) is given by y(x,t)=0.06sin⁡(2π3x)cos⁡(120πt)y(x, t) = 0.06 \sin \left(\frac{2\pi}{3} x\right) \cos (120 \pi t) where xx and yy are in m and tt in s. The length of the string is 1.5 m and its mass is 3.0×10−23.0 \times 10^{-2} kg.

(a)

Does the function represent a travelling wave or a stationary wave?

Answer

The function represents a stationary wave because the equation has the form y(x,t) = A sin(kx) cos(ωt), where the spatial part sin(kx) and temporal part cos(ωt) are separated. This is characteristic of stationary waves formed by superposition of two travelling waves.

(b)

Interpret the wave as a superposition of two waves travelling in opposite directions. What is the wavelength, frequency, and speed of each wave?

Answer

Wavelength = 3 m, Frequency = 60 Hz, Speed = 180 m/s for each travelling wave.

(c)

Determine the tension in the string.

Answer

Tension in the string = 648 N

Explanation

This question tests understanding of stationary waves, wave superposition, and the relationship between wave speed and string tension. The given equation y(x,t) = 0.06 sin(2πx/3) cos(120πt) is a product of separate spatial and temporal functions, which is the defining characteristic of stationary waves. Using the trigonometric identity sin A cos B = (1/2)[sin(A+B) + sin(A-B)], the wave can be decomposed into two travelling waves moving in opposite directions. The wave parameters are extracted by comparing with standard forms, and tension is calculated using the wave speed formula for stretched strings.