Question 17 of 17advanced🔧 ApplyNumerical3 marks

The Sun is a hot plasma (ionized matter) with its inner core at a temperature exceeding 10⁷ K, and its outer surface at a temperature of about 6000 K. At these high temperatures, no substance remains in a solid or liquid phase. In what range do you expect the mass density of the Sun to be, in the range of densities of solids and liquids or gases? Check if your guess is correct from the following data: mass of the Sun = 2.0×102.0 \times 10³⁰ kg, radius of the Sun = 7.0×107.0 \times 10⁸ m.

Correct Answer

The mass density of the Sun is approximately 1.4×101.4 \times 10³ kg/m³, which lies in the range of densities of solids and liquids, not gases. This is contrary to the initial expectation that a hot plasma would have gas-like density.

Calculation: Given: Mass of Sun = 2.0×102.0 \times 10³⁰ kg, Radius of Sun = 7.0×107.0 \times 10⁸ m

Volume of Sun (assuming spherical shape): V = (4/3)πr³ = (4/3) × π × (7.0×107.0 \times 10⁸)³ V = (4/3) × π × 343×10343 \times 10²⁴ = 1.44×101.44 \times 10²⁷ m³

Density of Sun: ρ = Mass/Volume = 2.0×102.0 \times 10³⁰ / 1.44×101.44 \times 10²⁷ ρ ≈\approx 1.4×101.4 \times 10³ kg/m³

This density is comparable to solids and liquids (water has density ~10³ kg/m³), whereas gases have densities around 1 kg/m³. Despite being a hot plasma at extremely high temperatures, the Sun's immense gravitational compression results in a density similar to solids and liquids.

Exercise: EXERCISES | Q: 1.17 | (Page 12)
For More Understanding

Explanation

This question tests understanding of density calculation and comparison with different states of matter. Students often incorrectly assume that since the Sun is plasma (ionized gas), its density should be gas-like. However, the calculation shows that gravitational compression makes the Sun's density comparable to solids and liquids. The key learning is that temperature alone doesn't determine density—gravitational forces play a crucial role in stellar objects.

Solution Steps

  1. Step 1: Identify given data - Mass = 2.0×102.0 \times 10³⁰ kg, Radius = 7.0×107.0 \times 10⁸ m

  2. Step 2: Calculate volume using sphere formula V = (4/3)πr³

  3. Step 3: Substitute r = 7.0×107.0 \times 10⁸ m to get V = 1.44×101.44 \times 10²⁷ m³

  4. Step 4: Calculate density ρ = Mass/Volume = 2.0×102.0 \times 10³⁰ / 1.44×101.44 \times 10²⁷

  5. Step 5: Compare result ($\approx$$$1.4 \times 10$$³ kg/m³) with typical densities of solids (~10³-10⁴ kg/m³), liquids (~10³ kg/m³), and gases (~1 kg/m³)