Question 5 of 18beginner🔧 ApplyNumerical3 marks

A 50 kg girl wearing high heel shoes balances on a single heel. The heel is circular with a diameter 1.0 cm. What is the pressure exerted by the heel on the horizontal floor?

Correct Answer

The pressure exerted by the heel on the horizontal floor is approximately 6.4×106.4 \times 10⁶ Pa.

Exercise: EXERCISES | Q: 9.5 | (Page 21)
For More Understanding

Explanation

This numerical problem is similar to Example 9.1 in the textbook, which calculates pressure using the formula P = F/A. The key steps involve calculating the weight of the girl as the force and determining the cross-sectional area of the circular heel. Using g = 10 m/s² (as done in Example 9.1), the force is 500 N. The area of the circular heel with diameter 1.0 cm (radius 0.5 cm = 0.005 m) is calculated using πr². The final pressure is obtained by dividing force by area.

Solution Steps

  1. Step 1: Calculate the force acting on the heel. The girl balances on a single heel, so her entire weight acts on it. F = mg = 50 kg × 10 m/s² = 500 N (taking g = 10 m/s² as per Example 9.1).

  2. Step 2: Calculate the area of the circular heel. Diameter = 1.0 cm, so radius r = 0.5 cm = 0.005 m. Area A = πr² = π × (0.005)² = π × 25×1025 \times 10⁻⁶ m² = 7.85×107.85 \times 10⁻⁵ m² (taking π = 3.14).

  3. Step 3: Calculate pressure using P = F/A. P = 500 N / (7.85×107.85 \times 10⁻⁵ m²) = 6.37×106.37 \times 10⁶ N m⁻² ≈\approx 6.4×106.4 \times 10⁶ Pa.