Question 32 of 70beginner🔧 ApplyShort Answer3 marks

Reduce the following equations into intercept form and find their intercepts on the axes.

(i)

3x+2y−12=03x + 2y - 12 = 0

Answer

Intercept form: x/4 + y/6 = 1; x-intercept = 4, y-intercept = 6

(ii)

4x−3y=64x - 3y = 6

Answer

Intercept form: x/(3/2) + y/(-2) = 1; x-intercept = 3/2, y-intercept = -2

(iii)

3y+2=03y + 2 = 0

Answer

This is a horizontal line y = -2/3; No x-intercept, y-intercept = -2/3

Explanation

The intercept form of a line is x/a + y/b = 1, where a is the x-intercept and b is the y-intercept. For each equation, we rearrange to isolate the constant term on the right side and divide to get the standard intercept form.