Question 48 of 70intermediate🔧 ApplyShort Answer3 marks

Find the values of kk for which the line (k−3)x−(4−k2)y+k2−7k+6=0(k - 3)x - (4 - k^2)y + k^2 - 7k + 6 = 0 is

(a)

Parallel to the xx-axis

Answer

k = 3

(b)

Parallel to the yy-axis

Answer

k = 2, -2

(c)

Passing through the origin

Answer

k = 6, 1

Explanation

To find the values of k, we apply the conditions for a line Ax + By + C = 0 based on the specific geometric properties requested. For part (a), a line is parallel to the x-axis only if the coefficient of x is zero (A=0). For part (b), a line is parallel to the y-axis only if the coefficient of y is zero (B=0). For part (c), similar to the concurrent lines example in the provided text where a point satisfies an equation, we substitute the origin's coordinates (0,0) into the given equation to find the required values.