If U = {1, 2, 3, 4, 5, 6, 7, 8, 9}, A = {2, 4, 6, 8} and B = {2, 3, 5, 7}. Verify that
(A ∪ B)' = A' ∩ B'
Given U = {1, 2, 3, 4, 5, 6, 7, 8, 9}, A = {2, 4, 6, 8} and B = {2, 3, 5, 7}.
Finding A' and B': A' = U - A = {1, 3, 5, 7, 9} B' = U - B = {1, 4, 6, 8, 9}
Finding LHS: A ∪ B = {2, 3, 4, 5, 6, 7, 8} (A ∪ B)' = {1, 9}
Finding RHS: A' ∩ B' = {1, 3, 5, 7, 9} ∩ {1, 4, 6, 8, 9} = {1, 9}
Since LHS = RHS = {1, 9}, we have verified that (A ∪ B)' = A' ∩ B'.
(A ∩ B)' = A' ∪ B'
Finding LHS: A ∩ B = {2} (A ∩ B)' = {1, 3, 4, 5, 6, 7, 8, 9}
Finding RHS: A' ∪ B' = {1, 3, 5, 7, 9} ∪ {1, 4, 6, 8, 9} = {1, 3, 4, 5, 6, 7, 8, 9}
Since LHS = RHS = {1, 3, 4, 5, 6, 7, 8, 9}, we have verified that (A ∩ B)' = A' ∪ B'.
Explanation
This question verifies De Morgan's Laws. For part (i), we find the complement of the union equals the intersection of complements. For part (ii), we find the complement of the intersection equals the union of complements. Both are verified by computing each side separately and showing equality.