Given the relation $R = \{(x, y): 3x - y = 0\}$, we can rewrite the condition as $y = 3x$. We need to find ordered pairs $(x, y)$ such that both $x$ and $y$ belong to set $A = \{1, 2, 3, \ldots, 14\}$.

By checking values for $x$ in $A$:

• If $x=1, y=3 \in A \implies (1, 3)$
• If $x=2, y=6 \in A \implies (2, 6)$
• If $x=3, y=9 \in A \implies (3, 9)$
• If $x=4, y=12 \in A \implies (4, 12)$
• If $x=5, y=15 \notin A$ (since $A$ ends at 14).

Thus, $R = \{(1, 3), (2, 6), (3, 9), (4, 12)\}$.

The Domain of $R$ is the set of first elements of the ordered pairs, which is $\{1, 2, 3, 4\}$.

The Range of $R$ is the set of second elements of the ordered pairs, which is $\{3, 6, 9, 12\}$.

Since the relation is defined from $A$ to $A$, the Codomain is set $A$ itself, which is $\{1, 2, 3, \ldots, 14\}$.