This limit involves trigonometric functions and uses the standard limits from Theorem 5 in the textbook. The key insight is to convert cosec x - cot x into a form where we can apply the standard limits. By expressing both terms with a common denominator of sin x, we get (1 - cos x)/sin x. Multiplying by x/x allows us to split this into two familiar limits: (1 - cos x)/x and x/sin x. Using the theorem that lim(x→0) (1 - cos x)/x = 0 and lim(x→0) sin x/x = 1 (which means lim(x→0) x/sin x = 1), we get $0 \times 1$ = 0.