Question 4 of 70beginner🔧 ApplyShort Answer1 mark

In each of the following Exercises 1 to 5, find the equation of the circle with centre (1, 1) and radius 2\sqrt{2}

Correct Answer

(x - 1)² + (y - 1)² = 2

Exercise: EXERCISE 10.1 | Q: 4 | (Page 6)
For More Understanding

Explanation

This question is from Exercise 10.1, Question 4. The standard equation of a circle with centre (h, k) and radius r is given by (x - h)² + (y - k)² = r². Here, h = 1, k = 1, and r = 2\sqrt{2}. Substituting these values gives (x - 1)² + (y - 1)² = (2\sqrt{2})² = 2.

Solution Steps

  1. Step 1: Recall the standard equation of a circle with centre (h, k) and radius r: (x - h)² + (y - k)² = r²

  2. Step 2: Identify the given values: h = 1, k = 1, r = 2\sqrt{2}

  3. Step 3: Substitute the values: (x - 1)² + (y - 1)² = (2\sqrt{2})²

  4. Step 4: Simplify: (x - 1)² + (y - 1)² = 2

PreviousNext