Question 26 of 28intermediate🔧 ApplyNumerical2 marks

Find the number of non-zero integral solutions of the equation ∣1−i∣x=2x|1 - i|^x = 2^x.

Correct Answer

0

Exercise: Miscellaneous Exercise on Chapter 4 | Q: 12 | (Page 10)
For More Understanding

Explanation

This question tests understanding of modulus of complex numbers and solving exponential equations. Students need to first calculate the modulus of the complex number 1 - i, then solve the resulting equation. The key insight is recognizing that the only solution is x = 0, which must be excluded since the question asks for non-zero integral solutions.

Solution Steps

  1. Step 1: Find the modulus of the complex number (1 - i).

    For a complex number a + bi, the modulus is |a + bi| = a2+b2\sqrt{a² + b²}.

    Therefore, |1 - i| = |1 + (-1)i| = 12+(−1\sqrt{1² + (-1}²) = 1+1\sqrt{1 + 1} = 2\sqrt{2}.

  2. Step 2: Substitute the value in the given equation.

    The equation becomes: (2\sqrt{2})^x = 2x2^{x}

  3. Step 3: Express both sides with the same base.

    Since 2\sqrt{2} = 2^(1/2), we have: (2^(1/2))^x = 2x2^{x} 2^(x/2) = 2x2^{x}

  4. Step 4: Equate the exponents.

    x/2 = x x - x/2 = 0 x/2 = 0 x = 0

  5. Step 5: Apply the constraint.

    The only solution is x = 0, but the question asks for non-zero integral solutions.

    Therefore, the number of non-zero integral solutions = 0.