Question 10 of 22intermediate🔧 ApplyLong Answer4 marks

Write a Python program to convert temperature in degree Celsius to degree Fahrenheit. If water boils at 100 degree C and freezes as 0 degree C, use the program to find out what is the boiling point and freezing point of water on the Fahrenheit scale. (Hint: T(°F) = T(°C) × 9/5 + 32)

Correct Answer

#Program to convert Celsius to Fahrenheit celsius = float(input("Enter temperature in Celsius: ")) fahrenheit = celsius * 9/5 + 32 print("Temperature in Fahrenheit:", fahrenheit)

#Finding boiling point (100°C) celsius_boil = 100 fahrenheit_boil = celsius_boil * 9/5 + 32 print("Boiling point of water:", fahrenheit_boil, "°F")

#Finding freezing point (0°C) celsius_freeze = 0 fahrenheit_freeze = celsius_freeze * 9/5 + 32 print("Freezing point of water:", fahrenheit_freeze, "°F")

Output: Boiling point of water: 212.0 °F Freezing point of water: 32.0 °F

Explanation: The program uses the formula T(°F) = T(°C) × 9/5 + 32 to convert temperature from Celsius to Fahrenheit. For the boiling point at 100°C, the calculation is: 100×9100 \times 9/5 + 32 = 180 + 32 = 212°F. For the freezing point at 0°C, the calculation is: 0×90 \times 9/5 + 32 = 0 + 32 = 32°F. The program demonstrates how arithmetic operators and variables work together to perform mathematical conversions.

Exercise: EXERCISE | Q: 10 | (Page 31)
For More Understanding

Explanation

This question tests the student's understanding of arithmetic operations and formula implementation in Python. The formula T(°F) = T(°C) × 9/5 + 32 is provided in the hint. Students should write a program that takes Celsius as input, applies the conversion formula, and outputs the Fahrenheit value. For the specific values: 100°C converts to 212°F (boiling point) and 0°C converts to 32°F (freezing point). The context mentions explicit type conversion and arithmetic operations which are relevant concepts here.

Solution Steps

  1. Step 1: Accept temperature in Celsius using input() function

  2. Step 2: Apply the conversion formula: fahrenheit = celsius * 9/5 + 32

  3. Step 3: For boiling point (100°C): 100×9100 \times 9/5 + 32 = 180 + 32 = 212°F

  4. Step 4: For freezing point (0°C): 0×90 \times 9/5 + 32 = 0 + 32 = 32°F

  5. Step 5: Display the results using print() function

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