The question tests understanding of operator precedence and how parentheses can override evaluation order. In Python, comparison operators (==, <, >) have equal precedence and are evaluated left to right. Chained comparisons like 'a == b == c' are evaluated as 'a == b and b == c'. By strategically placing parentheses, we can change the evaluation order. In (a), '1 == 2' evaluates to False (which equals 0), making '0 == False' True. In (b), '3 == 4' evaluates to False (0), so '2 + 0 + 5 == 7' becomes True. In (c), both comparisons evaluate to False, and 'False == False' is True.