Which of the following are isoelectronic species i.e., those having the same number of electrons? Na⁺, K⁺, Mg²⁺, Ca²⁺, S²⁻, Ar
Na⁺ and Mg²⁺ are isoelectronic species as they both have 10 electrons.
K⁺, Ca²⁺, S²⁻, and Ar are isoelectronic species as they all have 18 electrons.
Explanation
To find isoelectronic species, we calculate the total number of electrons in each given ion and atom. Na has 11 electrons, so Na⁺ has 10. Mg has 12 electrons, so Mg²⁺ has 10. Thus, Na⁺ and Mg²⁺ are isoelectronic. Ar has 18 electrons. K has 19 electrons, so K⁺ has 18. Ca has 20 electrons, so Ca²⁺ has 18. S has 16 electrons, so S²⁻ has 18. Thus, K⁺, Ca²⁺, S²⁻, and Ar are isoelectronic.
Solution Steps
Step 1: Calculate electrons for Na⁺ and Mg²⁺. Na has configuration (11 electrons). Na⁺ loses 1 electron, leaving 10 electrons. Mg is the next element after Na, so it has 12 electrons. Mg²⁺ loses 2 electrons, leaving 10 electrons. Therefore, Na⁺ and Mg²⁺ are isoelectronic.
Step 2: Calculate electrons for Ar, K⁺, Ca²⁺, and S²⁻. Ar has configuration (18 electrons). K is after Ar, so it has 19 electrons; K⁺ loses 1 electron, leaving 18 electrons. Ca is after K, so it has 20 electrons; Ca²⁺ loses 2 electrons, leaving 18 electrons. S is two elements before Ar, so it has 16 electrons; S²⁻ gains 2 electrons, reaching 18 electrons. Therefore, K⁺, Ca²⁺, S²⁻, and Ar are isoelectronic.