Question 46 of 62intermediate🔧 ApplyNumerical3 marks

Neon gas is generally used in the sign boards. If it emits strongly at 616 nm, calculate (a) the frequency of emission, (b) distance traveled by this radiation in 30 s (c) energy of quantum and (d) number of quanta present if it produces 2 J of energy.

(a)
Answer

4.87×10144.87 \times 10^{14} s−1^{-1}

(b)
Answer

9.0×1099.0 \times 10^{9} m

(c)
Answer

3.23×10−193.23 \times 10^{-19} J

(d)
Answer

6.2×10186.2 \times 10^{18}

Explanation

To solve this problem, we use the fundamental wave equation c=νλc = \nu\lambda and Planck's quantum equation E=hν=hcλE = h\nu = \frac{hc}{\lambda}. The speed of light cc is 3×1083 \times 10^8 m s−1^{-1} and Planck's constant hh is 6.626×10−346.626 \times 10^{-34} J s. The given wavelength is 616616 nm, which must be converted to meters (616×10−9616 \times 10^{-9} m) for calculations.

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