Question 6 of 62beginner🔧 ApplyNumerical2 marks

Find energy of each of the photons which (i) correspond to light of frequency 3×103 \times 10¹⁵ Hz. (ii) have wavelength of 0.50 Å.

(i)
Answer

1.9878×10−181.9878 \times 10^{-18} J

(ii)
Answer

3.9756×10−153.9756 \times 10^{-15} J

Explanation

The energy of a photon can be calculated using Planck's equation, E=hvE = hv, when frequency is given, and E=hcλE = \frac{hc}{\lambda} when wavelength is given. The constants used are Planck's constant h=6.626×10−34h = 6.626 \times 10^{-34} J s and the speed of light c=3×108c = 3 \times 10^8 m s⁻¹.

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