Question 26 of 62intermediate🔧 ApplyShort Answer2 marks

An atom of an element contains 29 electrons and 35 neutrons. Deduce (i) the number of protons and (ii) the electronic configuration of the element.

(i)
Answer

29

(ii)
Answer

1s22s22p63s23p64s13d101s^2 2s^2 2p^6 3s^2 3p^6 4s^1 3d^{10} (or 1s22s22p63s23p63d104s11s^2 2s^2 2p^6 3s^2 3p^6 3d^{10} 4s^1)

Explanation

For a neutral atom, the number of protons is equal to the number of electrons. Since the atom contains 29 electrons, it must also contain 29 protons. Therefore, the atomic number (Z) of the element is 29. The electronic configuration is determined by filling the 29 electrons into atomic orbitals in order of increasing energy, in accordance with the Pauli exclusion principle and Hund's rule of maximum multiplicity. For Z=29, the completely filled and half-filled/fully-filled subshell stability leads to the configuration 1s22s22p63s23p64s13d101s^2 2s^2 2p^6 3s^2 3p^6 4s^1 3d^{10}.