Question 9 of 62intermediate🔧 ApplyNumerical3 marks

A photon of wavelength 4×104 \times 10⁻⁷ m strikes on metal surface, the work function of the metal being 2.13 eV. Calculate (i) the energy of the photon (eV), (ii) the kinetic energy of the emission, and (iii) the velocity of the photoelectron (1 eV = 1.6020×101.6020 \times 10⁻¹⁹ J).

(i)
Answer

3.10 eV

(ii)
Answer

0.97 eV (or 1.5539×10−191.5539 \times 10^{-19} J)

(iii)
Answer

5.84×1055.84 \times 10^5 m/s

Explanation

The problem applies the photoelectric effect equation, where the energy of an incident photon is used to overcome the work function of the metal, and the excess energy is converted into the kinetic energy of the emitted photoelectron. The energy of the photon is calculated using E=hc/λE = hc/\lambda, converted to eV, and then used to find the kinetic energy. Finally, the velocity is determined using the kinetic energy formula.

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