Question 22 of 36beginner🔧 ApplyNumerical3 marks

If the speed of light is 3.0×103.0 \times 10⁸ m s⁻¹, calculate the distance covered by light in 2.00 ns.

Correct Answer

The distance covered by light in 2.00 ns is 0.600 m.

Exercise: EXERCISES | Q: 1.22 | (Page 27)
For More Understanding

Explanation

To find the distance covered by light, we use the fundamental relation between distance, speed, and time. The speed of light is given in meters per second (m s−1^{-1}), while the time is given in nanoseconds (ns). We must first convert the time into the SI unit of seconds (s) before multiplying it by the speed to find the distance in meters.

Solution Steps

  1. Step 1: Identify the given values. Speed of light (cc) = 3.0×1083.0 \times 10^8 m s−1^{-1}, Time (tt) = 2.00 ns.

  2. Step 2: Convert time from nanoseconds to seconds. Since 1 ns=10−9 s1 \text{ ns} = 10^{-9} \text{ s}, t=2.00×10−9 st = 2.00 \times 10^{-9} \text{ s}.

  3. Step 3: Apply the formula for distance. Distance (dd) = Speed (cc) ×\times Time (tt).

  4. Step 4: Calculate the distance. d=(3.0×108 m s−1)×(2.00×10−9 s)=6.0×10−1 m=0.600 md = (3.0 \times 10^8 \text{ m s}^{-1}) \times (2.00 \times 10^{-9} \text{ s}) = 6.0 \times 10^{-1} \text{ m} = 0.600 \text{ m}.

PreviousNext