Question 26 of 36intermediate🔧 ApplyNumerical3 marks

If 10 volumes of dihydrogen gas reacts with five volumes of dioxygen gas, how many volumes of water vapour would be produced?

Correct Answer

10 volumes of water vapour would be produced.

Exercise: EXERCISES | Q: 1.26 | (Page 27)
For More Understanding

Explanation

According to Gay Lussac’s Law of Gaseous Volumes and Avogadro's Law, gases combine in a simple ratio by volume. The reaction between dihydrogen and dioxygen to form water vapour occurs in a 2:1:2 volume ratio. Therefore, 10 volumes of dihydrogen reacting with 5 volumes of dioxygen will yield 10 volumes of water vapour.

Solution Steps

  1. Step 1: Write the balanced chemical reaction for the formation of water vapour: Hydrogen+Oxygen→Water\text{Hydrogen} + \text{Oxygen} \rightarrow \text{Water}

  2. Step 2: According to Gay Lussac’s Law and Avogadro's Law, two volumes of hydrogen combine with one volume of oxygen to give two volumes of water vapour. Thus, the volume ratio is 2:1:22:1:2.

  3. Step 3: The given volumes are 10 volumes of dihydrogen and 5 volumes of dioxygen. The ratio of given volumes is 10:510:5, which simplifies to 2:12:1.

  4. Step 4: Since the given volumes are in the exact required ratio, 10 volumes of dihydrogen will completely react with 5 volumes of dioxygen to produce 1010 volumes of water vapour.