Question 5 of 36intermediate🔧 ApplyNumerical3 marks

Calculate the mass of sodium acetate (CH₃COONa) required to make 500 mL of 0.375 molar aqueous solution. Molar mass of sodium acetate is 82.0245 g mol⁻¹.

Correct Answer

15.38 g

Exercise: EXERCISES | Q: 1.5 | (Page 25)
For More Understanding

Explanation

To find the mass of sodium acetate required, we first calculate the number of moles needed using the given molarity and volume of the solution. Then, we multiply the number of moles by the given molar mass of sodium acetate to obtain the required mass.

Solution Steps

  1. Given data: Molarity of sodium acetate solution = 0.375 M0.375 \text{ M}, Volume of solution = 500 mL=0.5 L500 \text{ mL} = 0.5 \text{ L}, Molar mass of sodium acetate = 82.0245 g mol−182.0245 \text{ g mol}^{-1}.

  2. Calculate moles: Moles of sodium acetate required = Molarity ×\times Volume (in L) = 0.375 mol L−1×0.5 L=0.1875 mol0.375 \text{ mol L}^{-1} \times 0.5 \text{ L} = 0.1875 \text{ mol}.

  3. Calculate mass: Mass of sodium acetate = Moles ×\times Molar mass = 0.1875 mol×82.0245 g mol−1=15.37959 g0.1875 \text{ mol} \times 82.0245 \text{ g mol}^{-1} = 15.37959 \text{ g}.

  4. Final Answer: The mass of sodium acetate required is 15.38 g15.38 \text{ g}.

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