Why does the following reaction occur? XeO₆⁴⁻ (aq) + 2F⁻ (aq) + 6H⁺(aq) → XeO₃(g) + F₂(g) + 3H₂O(l) What conclusion about the compound Na₄XeO₆ (of which XeO₆⁴⁻ is a part) can be drawn from the reaction.
(i) The reaction occurs because it is a redox reaction. In this reaction, the oxidation state of Xe decreases from in to in , meaning Xe is reduced. Simultaneously, the oxidation state of F increases from in to in , meaning F is oxidised. Since both oxidation and reduction occur simultaneously, the reaction takes place.
(ii) The conclusion drawn is that the compound (or ) acts as an extremely powerful oxidising agent. This is because it is capable of oxidising ions to gas, which is otherwise very difficult to achieve by chemical means.
Explanation
In the given reaction, Xe undergoes reduction and F undergoes oxidation. The oxidation state of Xe changes from +8 to +6, while F changes from -1 to 0. The context highlights that converting F- to F2 is extremely difficult and usually requires electrolytic oxidation. Therefore, a chemical agent that can oxidize F- to F2 must be an exceptionally strong oxidizing agent.
Solution Steps
Step 1: Determine the oxidation states of Xe and F in reactants and products. Xe in is and in is . F in is and in is .
Step 2: Identify the redox process. Xe is reduced () and F is oxidised (). This simultaneous oxidation and reduction drives the reaction.
Step 3: Draw the conclusion. Since oxidises to (which is very hard to do chemically), is a very powerful oxidising agent.